C++: Program to format Date And Time structure

 

 Format Date and Time in C++

Introduction:

The tm structure is very important while working with date and time in either C or C++.

This structure holds the date and time in the form of a C structure as mentioned above. Most of the time-related functions make use of tm structure. Following is an example which makes use of various date and time-related functions and tm structure :

While using structure in this chapter, I'm making an assumption that you have basic understanding on C structure and how to access structure members using arrow -> operator.


Program to Format Date and Time in C++ :

OUTPUT:



That's it for this blog. Hope you learned something new today :)


Comments

Post a Comment

Popular posts from this blog

OOP Assignment 3 helping materials

 Following is the code that will help you in the assignment for the addition of the arrays using operator overloading and returning an object. #include<iostream> using namespace std; int num; struct add {     int ar[20]; }; add operator+(add &a1,add &a2) {     add a3;     for(int i=0;i<num;i++)         a3.ar[i]=a2.ar[i]+a1.ar[i];     return a3; } int main() {     add a1,a2,a3;     cout<<"How many elements to be stored (max 20) : ";     cin>>num;     cout<<"Enter elements of array a1 : ";     for(int i=0;i<num;i++)         cin>>a1.ar[i];     cout<<"Enter elements of array a2 : ";     for(int i=0;i<num;i++)         cin>>a2.ar[i];     a3=a1+a2;     cout<<"Addition of two arrays : ";     for(int i=0;i<num;i++)   ...
Read more

Square root Algorithm in C++

 Here is the way you can find the square root of any number by writing your own code in c++.  #include<iostream> using namespace std; double sqrt(double num){ double stop_condition = 0.00000001; double guess = num/2; while((guess-num/guess) > stop_condition){ guess = (guess+num/2)/2; } return guess; } int main(){ double num = 4; cout<<"The result is: "<<sqrt(num)<<endl; return 0; }
Read more

OOP lab 7 task solution

  #include <iostream> using namespace std ; class position { public: int x ; int y ; position (){ x = 0 ; y = 0 ; } position operator + ( position & p_any ){ position p1 ; p1 . x = this -> x + p_any . x ; p1 . y = this -> y + p_any . y ; return p1 ; } }; int main (){ position p1 ; cout<< "Enter the intial values of x and y cordinates: " ; cin>> p1 . x >> p1 . y ; position p2 ; cout<< "Enter the new values for x and y to be shifted: " ; cin>> p2 . x >> p2 . y ; position p3 ; p3 = p1 + p2 ; cout<< "The initial values were: " << p1 . x << " " << p1 . y <<endl; cout<< "The new values are: " << p3 . x << " " << p3 . y <<endl; } // from now onward this is the second task #in...
Read more